Lemma 15.79.3. Let R be a Noetherian regular ring of dimension d < \infty . Let K, L \in D^-(R). Assume there exists an k such that H^ i(K) = 0 for i \leq k and H^ i(L) = 0 for i \geq k - d + 1. Then \mathop{\mathrm{Hom}}\nolimits _{D(R)}(K, L) = 0.
Proof. Let K^\bullet be a bounded above complex representing K, say K^ i = 0 for i \geq n + 1. After replacing K^\bullet by \tau _{\geq k + 1}K^\bullet we may assume K^ i = 0 for i \leq k. Then we may use the distinguished triangle
to see it suffices to prove the lemma for K^ n[-n] and \sigma _{\leq n - 1}K^\bullet . By induction on n, we conclude that it suffices to prove the lemma in case K is represented by the complex M[-m] for some R-module M and some m \geq k + 1. Since R has global dimension d by Algebra, Lemma 10.110.8 we see that M has a projective resolution 0 \to P_ d \to \ldots \to P_0 \to M \to 0. Then the complex P^\bullet having P_ i in degree m - i is a bounded complex of projectives representing M[-m]. On the other hand, we can choose a complex L^\bullet representing L with L^ i = 0 for i \geq k - d + 1. Hence any map of complexes P^\bullet \to L^\bullet is zero. This implies the lemma by Derived Categories, Lemma 13.19.8. \square
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