Lemma 20.34.6. Let (X, \mathcal{O}_ X) be a ringed space. Let i : Z \to X be the inclusion of a closed subset. Denote j : U = X \setminus Z \to X the inclusion of the complement. There is a distinguished triangle
i_*R\mathcal{H}_ Z(K) \to K \to Rj_*(K|_ U) \to i_*R\mathcal{H}_ Z(K)[1]
in D(\mathcal{O}_ X) functorial for K in D(\mathcal{O}_ X).
Proof.
Choose a K-injective complex \mathcal{I}^\bullet all of whose terms are injective \mathcal{O}_ X-modules representing K. See Section 20.28. Recall that \mathcal{I}^\bullet |_ U is a K-injective complex of \mathcal{O}_ U-modules, see Lemma 20.32.1. Hence each of the derived functors in the distinguished triangle is gotten by applying the underlying functor to \mathcal{I}^\bullet . Hence it suffices to prove that for an injective \mathcal{O}_ X-module \mathcal{I} we have a short exact sequence
0 \to i_*\mathcal{H}_ Z(\mathcal{I}) \to \mathcal{I} \to j_*(\mathcal{I}|_ U) \to 0
This follows from Lemma 20.8.1 and the definitions.
\square
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