The Stacks project

Lemma 18.24.2. Let $\mathcal{C}$ be a category viewed as a site with the chaotic topology, see Sites, Example 7.6.6. Let $\mathcal{O}$ be a sheaf of rings on $\mathcal{C}$ and let $\mathcal{F}$ be a sheaf of $\mathcal{O}$-modules. Then $\mathcal{F}$ is quasi-coherent if and only if for all $U \to V$ in $\mathcal{C}$ the canonical map

\[ \mathcal{F}(V) \otimes _{\mathcal{O}(V)} \mathcal{O}(U) \longrightarrow \mathcal{F}(U) \]

is an isomorphism.

Proof. Assume $\mathcal{F}$ is quasi-coherent and let $U \to V$ be a morphism of $\mathcal{C}$. Since every covering of $V$ is given by an isomorphism we conclude from Definition 18.23.1 that there exists a presentation

\[ \bigoplus \nolimits _{j \in J} \mathcal{O}_ V \longrightarrow \bigoplus \nolimits _{i \in I} \mathcal{O}_ V \longrightarrow \mathcal{F}|_{\mathcal{C}/V} \longrightarrow 0 \]

Since the topology on $\mathcal{C}$ is chaotic, taking sections over any object of $\mathcal{C}$ is exact. We conclude that we obtain a presentation

\[ \bigoplus \nolimits _{j \in J} \mathcal{O}(V) \longrightarrow \bigoplus \nolimits _{i \in I} \mathcal{O}(V) \longrightarrow \mathcal{F}(V) \longrightarrow 0 \]

of $\mathcal{F}(V)$ as an $\mathcal{O}(V)$-module and similarly for $\mathcal{F}(U)$. This easily shows that the displayed map in the statement of the lemma is an isomorphism.

Assume the displayed map in the statement of the lemma is an isomorphism for every morphism $U \to V$ in $\mathcal{C}$. Fix $V$ and choose a presentation

\[ \bigoplus \nolimits _{j \in J} \mathcal{O}(V) \longrightarrow \bigoplus \nolimits _{i \in I} \mathcal{O}(V) \longrightarrow \mathcal{F}(V) \longrightarrow 0 \]

of $\mathcal{F}(V)$ as an $\mathcal{O}(V)$-module. Then the assumption on $\mathcal{F}$ exactly means that the corresponding sequence

\[ \bigoplus \nolimits _{j \in J} \mathcal{O}_ V \longrightarrow \bigoplus \nolimits _{i \in I} \mathcal{O}_ V \longrightarrow \mathcal{F}|_{\mathcal{C}/V} \longrightarrow 0 \]

is exact and we conclude that $\mathcal{F}$ is quasi-coherent. $\square$

Comments (0)

Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 0GZN. Beware of the difference between the letter 'O' and the digit '0'.



View Lemma 18.24.2 as pdf