Lemma 4.14.11. Let $M : \mathcal{I} \to \mathcal{C}$ be a diagram. Write $I = \mathop{\mathrm{Ob}}\nolimits (\mathcal{I})$ and $A = \text{Arrows}(\mathcal{I})$. Denote $s, t : A \to I$ the source and target maps. Suppose that $\coprod _{i \in I} M_ i$ and $\coprod _{a \in A} M_{s(a)}$ exist. Suppose that the coequalizer of

exists, where the morphisms are determined by their components as follows: The component $M_{s(a)}$ maps via $\psi $ to the component $M_{t(a)}$ via the morphism $a$. The component $M_{s(a)}$ maps via $\phi $ to the component $M_{s(a)}$ by the identity morphism. Then this coequalizer is the colimit of the diagram.

## Comments (1)

Comment #981 by Johan Commelin on

There are also: