The Stacks project

Lemma 10.104.7. Suppose $R$ is a Noetherian Cohen-Macaulay ring. Any polynomial algebra over $R$ is Cohen-Macaulay.

Proof. Special case of Lemma 10.103.13. $\square$

Comments (2)

Comment #2982 by Dario Weißmann on

The lemma only holds for finite type polynomial algebras.

Comment #3106 by on

Well, I think that is what polynomial algebra means unless you specify "infinitely many variables". So I am going to leave as is for now.

There are also:

  • 7 comment(s) on Section 10.104: Cohen-Macaulay rings

Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 00ND. Beware of the difference between the letter 'O' and the digit '0'.



View Lemma 10.104.7 as pdf