Loading web-font TeX/Math/Italic

The Stacks project

Lemma 10.115.5. Let k be a field. Let S be a finite type k algebra and denote X = \mathop{\mathrm{Spec}}(S). Let \mathfrak q be a prime of S, and let x \in X be the corresponding point. There exists a g \in S, g \not\in \mathfrak q such that \dim (S_ g) = \dim _ x(X) =: d and such that there exists a finite injective map k[y_1, \ldots , y_ d] \to S_ g.

Proof. Note that by definition \dim _ x(X) is the minimum of the dimensions of S_ g for g \in S, g \not\in \mathfrak q, i.e., the minimum is attained. Thus the lemma follows from Lemma 10.115.4. \square


Comments (2)

Comment #941 by JuanPablo on

Maybe there should be references to tags 00OK and 00OP, to see that the number of is the same as the dimension of .

Comment #942 by JuanPablo on

Ah! nevermind, that is included in the last lemma.

There are also:

  • 2 comment(s) on Section 10.115: Noether normalization

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.