Lemma 12.29.3. Let \mathcal{A} and \mathcal{B} be abelian categories. Let u : \mathcal{A} \to \mathcal{B} and v : \mathcal{B} \to \mathcal{A} be additive functors. Assume
u is right adjoint to v,
v transforms injective maps into injective maps,
\mathcal{A} has enough injectives, and
vB = 0 implies B = 0 for any B \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{B}).
Then \mathcal{B} has enough injectives.
Comments (0)
There are also: