Lemma 14.2.2. Any morphism in \Delta can be written as a composition of the morphisms \delta ^ n_ j and \sigma ^ n_ j.
Proof. Let \varphi : [n] \to [m] be a morphism of \Delta . If j \not\in \mathop{\mathrm{Im}}(\varphi ), then we can write \varphi as \delta ^ m_ j \circ \psi for some morphism \psi : [n] \to [m - 1]. If \varphi (j) = \varphi (j + 1) then we can write \varphi as \psi \circ \sigma ^{n - 1}_ j for some morphism \psi : [n - 1] \to [m]. The result follows because each replacement as above lowers n + m and hence at some point \varphi is both injective and surjective, hence an identity morphism. \square
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