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The Stacks project

Lemma 14.19.10. Let \mathcal{C} be a category which has finite limits.

  1. For every n the functor \text{sk}_ n : \text{Simp}(\mathcal{C}) \to \text{Simp}_ n(\mathcal{C}) has a right adjoint \text{cosk}_ n.

  2. For every n' \geq n the functor \text{sk}_ n : \text{Simp}_{n'}(\mathcal{C}) \to \text{Simp}_ n(\mathcal{C}) has a right adjoint, namely \text{sk}_{n'}\text{cosk}_ n.

  3. For every m \geq n \geq 0 and every n-truncated simplicial object U of \mathcal{C} we have \text{cosk}_ m \text{sk}_ m \text{cosk}_ n U = \text{cosk}_ n U.

  4. If U is a simplicial object of \mathcal{C} such that the canonical map U \to \text{cosk}_ n \text{sk}_ nU is an isomorphism for some n \geq 0, then the canonical map U \to \text{cosk}_ m \text{sk}_ mU is an isomorphism for all m \geq n.

Proof. The existence in (1) follows from Lemma 14.19.2 above. Parts (2) and (3) follow from the discussion in Remark 14.19.9. After this (4) is obvious. \square


Comments (1)

Comment #1023 by correction_bot on

The first sentence of the proof seems strange. Maybe something more like

"The existence in (1) follows from Lemma \ref{lemma-existence-cosk} above. (2) and (3) follow from the discussion in Remark \ref{remark-inductive-coskelet}."

was intended.

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  • 4 comment(s) on Section 14.19: Coskeleton functors

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