Lemma 29.11.12 (01SH)—The Stacks project

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Table of contents
Part 2: Schemes
Chapter 29: Morphisms of Schemes
Section 29.11: Affine morphisms
Lemma 29.11.12 (cite)

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Lemma 29.11.12. A morphism between affine schemes is affine.

Proof. Immediate from Lemma 29.11.11 with $S = \mathop{\mathrm{Spec}}(\mathbf{Z})$ . It also follows directly from the equivalence of (1) and (2) in Lemma 29.11.3. $\square$

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Comment #832 by Johan Commelin on July 24, 2014 at 18:01

Suggested slogan: A morphism between affine schemes is affine.

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