Lemma 29.44.3. Let f : X \to S be a morphism of schemes. The following are equivalent:
The morphism f is finite.
There exists an affine open covering S = \bigcup U_ i such that each f^{-1}(U_ i) is affine and \mathcal{O}_ S(U_ i) \to \mathcal{O}_ X(f^{-1}(U_ i)) is finite.
There exists an open covering S = \bigcup U_ i such that each f^{-1}(U_ i) \to U_ i is finite.
Moreover, if f is finite then for every open subscheme U \subset S the morphism f : f^{-1}(U) \to U is finite.
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Comment #211 by Rex on