The Stacks project

Lemma 32.8.3. Notation and assumptions as in Situation 32.8.1. If

  1. $f$ is a finite morphism, and

  2. $f_0$ is locally of finite type,

then there exists an $i \geq 0$ such that $f_ i$ is finite.

Proof. A finite morphism is affine, see Morphisms, Definition 29.44.1. Hence by Lemma 32.8.2 above after increasing $0$ we may assume that $f_0$ is affine. By writing $Y_0$ as a finite union of affines we reduce to proving the result when $X_0$ and $Y_0$ are affine and map into a common affine $W \subset S_0$. The corresponding algebra statement follows from Algebra, Lemma 10.168.3. $\square$


Comments (0)

There are also:

  • 5 comment(s) on Section 32.8: Descending properties of morphisms

Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 01ZO. Beware of the difference between the letter 'O' and the digit '0'.