Lemma 65.6.2. A scheme is an algebraic space. More precisely, given a scheme T \in \mathop{\mathrm{Ob}}\nolimits ((\mathit{Sch}/S)_{fppf}) the representable functor h_ T is an algebraic space.
Proof. The functor h_ T is a sheaf by our remarks in Section 65.2. The diagonal h_ T \to h_ T \times h_ T = h_{T \times T} is representable because (\mathit{Sch}/S)_{fppf} has fibre products. The identity map h_ T \to h_ T is surjective étale. \square
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