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The Stacks project

Lemma 42.68.37. Let A be a discrete valuation ring with fraction field K. For nonzero x, y \in K we have

d_ A(x, y) = (-1)^{\text{ord}_ A(x)\text{ord}_ A(y)} \frac{x^{\text{ord}_ A(y)}}{y^{\text{ord}_ A(x)}} \bmod \mathfrak m_ A,

in other words the symbol is equal to the usual tame symbol.

Proof. By multiplicativity it suffices to prove this when x, y \in A. Let t \in A be a uniformizer. Write x = t^ bu and y = t^ bv for some a, b \geq 0 and u, v \in A^*. Set l = a + b. Then t^{l - 1}, \ldots , t^ b is an admissible sequence in (x)/(xy) and t^{l - 1}, \ldots , t^ a is an admissible sequence in (y)/(xy). Hence by Remark 42.68.14 we see that d_ A(x, y) is characterized by the equation

[t^{l - 1}, \ldots , t^ b, v^{-1}t^{b - 1}, \ldots , v^{-1}] = (-1)^{ab} d_ A(x, y) [t^{l - 1}, \ldots , t^ a, u^{-1}t^{a - 1}, \ldots , u^{-1}].

Hence by the admissible relations for the symbols [x_1, \ldots , x_ l] we see that

d_ A(x, y) = (-1)^{ab} u^ a/v^ b \bmod \mathfrak m_ A

as desired. \square


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