The Stacks project

Lemma 42.36.1. Let $(S, \delta )$ be as in Situation 42.7.1. Let $X$ be locally of finite type over $S$. Let $\mathcal{E}$ be a finite locally free $\mathcal{O}_ X$-module $\mathcal{E}$ of rank $r$. Let $(\pi : P \to X, \mathcal{O}_ P(1))$ be the projective bundle associated to $\mathcal{E}$. For any $\alpha \in \mathop{\mathrm{CH}}\nolimits _ k(X)$ the element

\[ \pi _*\left( c_1(\mathcal{O}_ P(1))^ s \cap \pi ^*\alpha \right) \in \mathop{\mathrm{CH}}\nolimits _{k + r - 1 - s}(X) \]

is $0$ if $s < r - 1$ and is equal to $\alpha $ when $s = r - 1$.

Proof. Let $Z \subset X$ be an integral closed subscheme of $\delta $-dimension $k$. Note that $\pi ^*[Z] = [\pi ^{-1}(Z)]$ as $\pi ^{-1}(Z)$ is integral of $\delta $-dimension $r - 1$. If $s < r - 1$, then by construction $c_1(\mathcal{O}_ P(1))^ s \cap \pi ^*[Z]$ is represented by a $(k + r - 1 - s)$-cycle supported on $\pi ^{-1}(Z)$. Hence the pushforward of this cycle is zero for dimension reasons.

Let $s = r - 1$. By the argument given above we see that $\pi _*(c_1(\mathcal{O}_ P(1))^ s \cap \pi ^*\alpha ) = n [Z]$ for some $n \in \mathbf{Z}$. We want to show that $n = 1$. For the same dimension reasons as above it suffices to prove this result after replacing $X$ by $X \setminus T$ where $T \subset Z$ is a proper closed subset. Let $\xi $ be the generic point of $Z$. We can choose elements $e_1, \ldots , e_{r - 1} \in \mathcal{E}_\xi $ which form part of a basis of $\mathcal{E}_\xi $. These give rational sections $s_1, \ldots , s_{r - 1}$ of $\mathcal{O}_ P(1)|_{\pi ^{-1}(Z)}$ whose common zero set is the closure of the image a rational section of $\mathbf{P}(\mathcal{E}|_ Z) \to Z$ union a closed subset whose support maps to a proper closed subset $T$ of $Z$. After removing $T$ from $X$ (and correspondingly $\pi ^{-1}(T)$ from $P$), we see that $s_1, \ldots , s_ n$ form a sequence of global sections $s_ i \in \Gamma (\pi ^{-1}(Z), \mathcal{O}_{\pi ^{-1}(Z)}(1))$ whose common zero set is the image of a section $Z \to \pi ^{-1}(Z)$. Hence we see successively that

\begin{eqnarray*} \pi ^*[Z] & = & [\pi ^{-1}(Z)] \\ c_1(\mathcal{O}_ P(1)) \cap \pi ^*[Z] & = & [Z(s_1)] \\ c_1(\mathcal{O}_ P(1))^2 \cap \pi ^*[Z] & = & [Z(s_1) \cap Z(s_2)] \\ \ldots & = & \ldots \\ c_1(\mathcal{O}_ P(1))^{r - 1} \cap \pi ^*[Z] & = & [Z(s_1) \cap \ldots \cap Z(s_{r - 1})] \end{eqnarray*}

by repeated applications of Lemma 42.25.4. Since the pushforward by $\pi $ of the image of a section of $\pi $ over $Z$ is clearly $[Z]$ we see the result when $\alpha = [Z]$. We omit the verification that these arguments imply the result for a general cycle $\alpha = \sum n_ j [Z_ j]$. $\square$


Comments (0)


Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 02TW. Beware of the difference between the letter 'O' and the digit '0'.