Lemma 42.39.1. Let $(S, \delta )$ be as in Situation 42.7.1. Let $X$ be locally of finite type over $S$. Let $\mathcal{E}$ be a finite locally free sheaf of rank $r$ on $X$. Let $\mathcal{L}$ be an invertible sheaf on $X$. Then we have
in $A^*(X)$.
Let $(S, \delta )$ be as in Situation 42.7.1. Let $X$ be locally of finite type over $S$. Let $\mathcal{E}_ i$ be a finite collection of finite locally free sheaves on $X$. By Lemma 42.38.9 we see that the Chern classes
generate a commutative (and even central) $\mathbf{Z}$-subalgebra of the Chow cohomology algebra $A^*(X)$. Thus we can say what it means for a polynomial in these Chern classes to be zero, or for two polynomials to be the same. As an example, saying that $c_1(\mathcal{E}_1)^5 + c_2(\mathcal{E}_2)c_3(\mathcal{E}_3) = 0$ means that the operations
are zero for all morphisms $f : Y \to X$ which are locally of finite type. By Lemma 42.35.3 this is equivalent to the requirement that given any morphism $f : Y \to X$ where $Y$ is an integral scheme locally of finite type over $S$ the cycle
is zero in $\mathop{\mathrm{CH}}\nolimits _{\dim (Y) - 5}(Y)$.
A specific example is the relation
proved in Lemma 42.25.2. More generally, here is what happens when we tensor an arbitrary locally free sheaf by an invertible sheaf.
Lemma 42.39.1. Let $(S, \delta )$ be as in Situation 42.7.1. Let $X$ be locally of finite type over $S$. Let $\mathcal{E}$ be a finite locally free sheaf of rank $r$ on $X$. Let $\mathcal{L}$ be an invertible sheaf on $X$. Then we have
in $A^*(X)$.
Proof. This should hold for any triple $(X, \mathcal{E}, \mathcal{L})$. In particular it should hold when $X$ is integral and by Lemma 42.35.3 it is enough to prove it holds when capping with $[X]$ for such $X$. Thus assume that $X$ is integral. Let $(\pi : P \to X, \mathcal{O}_ P(1))$, resp. $(\pi ' : P' \to X, \mathcal{O}_{P'}(1))$ be the projective space bundle associated to $\mathcal{E}$, resp. $\mathcal{E} \otimes \mathcal{L}$. Consider the canonical morphism
see Constructions, Lemma 27.20.1. It has the property that $g^*\mathcal{O}_{P'}(1) = \mathcal{O}_ P(1) \otimes \pi ^* {\mathcal L}$. This means that we have
in $\mathop{\mathrm{CH}}\nolimits _*(P)$, where $\xi $ represents $c_1(\mathcal{O}_ P(1))$ and $x$ represents $c_1(\pi ^*\mathcal{L})$. By simple algebra this is equivalent to
Comparing with Equation (42.37.1.1) it follows from this that
Reworking this (getting rid of minus signs, and renumbering) we get the desired relation. $\square$
Some example cases of (42.39.1.1) are
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