Lemma 28.13.6. Let X be a scheme. The following are equivalent:
The scheme X is Nagata.
For every affine open U \subset X the ring \mathcal{O}_ X(U) is Nagata.
There exists an affine open covering X = \bigcup U_ i such that each \mathcal{O}_ X(U_ i) is Nagata.
There exists an open covering X = \bigcup X_ j such that each open subscheme X_ j is Nagata.
Moreover, if X is Nagata then every open subscheme is Nagata.
Comments (0)