Lemma 29.44.15 (03BB)—The Stacks project

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Table of contents
Part 2: Schemes
Chapter 29: Morphisms of Schemes
Section 29.44: Integral and finite morphisms
Lemma 29.44.15 (cite)

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Lemma 29.44.15. Let $f : X \to Y$ be a morphism of schemes. If $f$ is finite and a monomorphism, then $f$ is a closed immersion.

Proof. This reduces to Algebra, Lemma 10.107.6. $\square$

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