History of tag 03KH
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changed the statement
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2022-01-23 |
9cee969 |
Try to use L/K notation for field extensions
We could also try to consistenly use "field extension" and not just
"extension" and consistently use "ring extension", etc.
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changed the proof
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2017-10-05 |
0adaa52 |
Remove 'f.f.'
Sad IMHO.
Thanks to BCnrd, Dario Weissmann, and sdf
https://stacks.math.columbia.edu/tag/02JQ#comment-2762
https://stacks.math.columbia.edu/tag/02JQ#comment-2765
https://stacks.math.columbia.edu/tag/02JQ#comment-2766
https://stacks.math.columbia.edu/tag/02JQ#comment-2767
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changed the statement
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2016-07-21 |
fc5a5ed |
valuation ---> valuative
Thanks toKestutis Cesnavicius
http://stacks.math.columbia.edu/tag/03K8#comment-2101
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changed the statement
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2014-04-21 |
4a83bc0 |
Valuative criteria
Thanks to Brian Conrad
Here is a part of his email concerning the topic of this commit:
"Here is a more direct way to say what is going on in the case of alg.
spaces, it case it might be of some use to include a Remark along such
lines in the Stacks Project. Let f:X ---> Y be a quasi-compact
separated map between quasi-separated alg. spaces. Let R be a valuation
ring with fraction field k, and suppose we are given y in Y(R) and x_k
in X(k) over the associated y_k in Y(k). We want to consider the
problem of whether x_k extends uniquely to an x in X(R) over y, and
possibly after some local extension on R to a bigger valuation ring. We
can at least pull back along y so that we may rename Y as Spec(R). That
is, we're give X = qc separated algebraic space over Spec(R), and x_k in
X(k). We wonder if it extends to X(R), possibly after some local
extension on R to a bigger valuation ring. Since X_k is separated, so
x_k is a closed immersion into X_k, there is no harm in replacing X with
the "schematic closure" of x_k.
This reduces our study to when X_k = Spec(k) and X is R-flat (as
flatness over val. ring is the same as being torsion-free). In such a
situation, the key thing is to show that X is univ. closed over Spec(R)
iff X = Spec(R). The implication "<==" is obvious, and for the converse
it suffices to show X is quasi-finite over Spec(R) (as then X is a
*scheme*, so we can apply the usual thing). To check being quasi-finite
it is harmless to make a local extension on R to a bigger valuation ring
since that is an fpqc base change (and such base change preserves the
hypotheses we have arranged to hold). But if we can make such a base
change to acquire a section then the section is a closed immersion (as X
is separated) and its defining ideal must vanish (since by R-flatness
this can be checked at the generic point, where all is clear)."
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changed the proof
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2013-07-02 |
5a9f757 |
Fix for xyjax error on Tag 089G
The fix is to make sure there is no &\Spec in xymatrix
However, having this doesn't trigger the bug consistently.
Anyway, the easiest solution for now is to make sure every
& is followed by a space in the LaTeX files.
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changed the proof
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2011-08-10 |
65ce54f |
LaTeX: \Spec
Introduced the macro
\def\Spec{\mathop{\rm Spec}}
and changed all the occurences of \text{Spec} into \Spec.
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changed the proof
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2010-10-09 |
2b090dd |
End conversion of etale to \'etale.
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assigned tag 03KH
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2009-11-11 |
22fbdba
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Morphisms of Spaces: Relative conditions
Trying to understand the relative versions of the local
conditions found in Properties of Spaces
Todo:
Fix currently unfinished discussion of the above
Add lemma about algebraic spaces etale over fields
When does an algebraic space satisfy the sheaf
condition for fpqc-coverings? This is missing in
the discussion of algebraic space in the
introductory chapter on algebraic spaces, but it
doesn't have a high priority.
Add remark discussing informally the relative conditions
and what to do with them.
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created statement with label lemma-finite-separable-enough in spaces-morphisms.tex
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2009-11-10 |
1b54d5d |
Morphisms of Spaces: Valuative criterion + finite separable extensions
In the existence part of the valuative criterion for algebraic
spaces it is enough to take a finite separable extension of the
fraction field of the dvr. It is sometimes also necessary. It
seems that if the morphism is separated, then it shouldn't be
necessary, but we'll return to that later.
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