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The Stacks project

Lemma 35.13.6. Let \{ f_ i : T_ i \to T\} _{i \in I} be a fpqc covering. Suppose that for each i we have an open subset W_ i \subset T_ i such that for all i, j \in I we have \text{pr}_0^{-1}(W_ i) = \text{pr}_1^{-1}(W_ j) as open subsets of T_ i \times _ T T_ j. Then there exists a unique open subset W \subset T such that W_ i = f_ i^{-1}(W) for each i.

Proof. Apply Lemma 35.13.1 to the map \coprod _{i \in I} T_ i \to T. It implies there exists a subset W \subset T such that W_ i = f_ i^{-1}(W) for each i, namely W = \bigcup f_ i(W_ i). To see that W is open we may work Zariski locally on T. Hence we may assume that T is affine. Using Topologies, Definition 34.9.1 we may choose a standard fpqc covering \{ g_ j : V_ j \to T\} _{j \in J} which refines \{ T_ i \to T\} _{i \in I}. Let \alpha : J \to I and h_ j : V_ j \to T_{\alpha (j)} be as in Sites, Definition 7.8.1. Then g_ j^{-1}(W) = h_ j^{-1}(W_{\alpha (j)}). Thus we may assume \{ f_ i : T_ i \to T\} is a standard fpqc covering. In this case we may apply Morphisms, Lemma 29.25.12 to the morphism \coprod T_ i \to T to conclude that W is open. \square


Comments (3)

Comment #7530 by WhatJiaranEatsTonight on

Could you please tell me how to reduce it to the case that is a standard fpqc covering?

Comment #7533 by on

In the proof we only do this reduction when we already have as a subset and is affine. By Definition 34.9.1 the covering can be refined by a standard one, say and maps to over . Then the pullback of to is also the pullback of and hence open. Maybe this should be added?

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  • 2 comment(s) on Section 35.13: Fpqc coverings are universal effective epimorphisms

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