Lemma 65.7.2. Let $S$ be a scheme contained in $\mathit{Sch}_{fppf}$. Let $H$ be a sheaf on $(\mathit{Sch}/S)_{fppf}$ whose diagonal is representable. Let $F, G$ be algebraic spaces over $S$. Let $F \to H$, $G \to H$ be maps of sheaves. Then $F \times _ H G$ is an algebraic space.

Proof. We check the 3 conditions of Definition 65.6.1. A fibre product of sheaves is a sheaf, hence $F \times _ H G$ is a sheaf. The diagonal of $F \times _ H G$ is the left vertical arrow in

$\xymatrix{ F \times _ H G \ar[r] \ar[d]_\Delta & F \times G \ar[d]^{\Delta _ F \times \Delta _ G} \\ (F \times F) \times _{(H \times H)} (G \times G) \ar[r] & (F \times F) \times (G \times G) }$

which is cartesian. Hence $\Delta$ is representable as the base change of the morphism on the right which is representable, see Lemmas 65.3.4 and 65.3.3. Finally, let $U, V \in \mathop{\mathrm{Ob}}\nolimits ((\mathit{Sch}/S)_{fppf})$ and $a : U \to F$, $b : V \to G$ be surjective and étale. As $\Delta _ H$ is representable, we see that $U \times _ H V$ is a scheme. The morphism

$U \times _ H V \longrightarrow F \times _ H G$

is surjective and étale as a composition of the base changes $U \times _ H V \to U \times _ H G$ and $U \times _ H G \to F \times _ H G$ of the étale surjective morphisms $U \to F$ and $V \to G$, see Lemmas 65.3.2 and 65.3.3. This proves the last condition of Definition 65.6.1 holds and we conclude that $F \times _ H G$ is an algebraic space. $\square$

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).