Lemma 100.8.5. A monomorphism of algebraic stacks induces an injective map of sets of points.
Monomorphisms of stacks are injective on points.
Proof. Let f : \mathcal{X} \to \mathcal{Y} be a monomorphism of algebraic stacks. Suppose that x_ i : \mathop{\mathrm{Spec}}(K_ i) \to \mathcal{X} be morphisms such that f \circ x_1 and f \circ x_2 define the same element of |\mathcal{Y}|. Applying the definition we find a common extension \Omega with corresponding morphisms c_ i : \mathop{\mathrm{Spec}}(\Omega ) \to \mathop{\mathrm{Spec}}(K_ i) and a 2-isomorphism \beta : f \circ x_1 \circ c_1 \to f \circ x_1 \circ c_2. As f is fully faithful, see Lemma 100.8.4, we can lift \beta to an isomorphism \alpha : x_1 \circ c_1 \to x_1 \circ c_2. Hence x_1 and x_2 define the same point of |\mathcal{X}| as desired. \square
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