Lemma 5.19.10. Let X be a Noetherian sober topological space. Let E \subset X be a subset of X.
If E is constructible and stable under specialization, then E is closed.
If E is constructible and stable under generalization, then E is open.
Lemma 5.19.10. Let X be a Noetherian sober topological space. Let E \subset X be a subset of X.
If E is constructible and stable under specialization, then E is closed.
If E is constructible and stable under generalization, then E is open.
Proof. Let E be constructible and stable under generalization. Let Y \subset X be an irreducible closed subset with generic point \xi \in Y. If E \cap Y is nonempty, then it contains \xi (by stability under generalization) and hence is dense in Y, hence it contains a nonempty open of Y, see Lemma 5.16.3. Thus E is open by Lemma 5.16.5. This proves (2). To prove (1) apply (2) to the complement of E in X. \square
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