Lemma 10.66.14. Let $R$ be a ring. Let $I$ be an ideal. Let $M$ be an $R/I$-module. Via the canonical injection $\mathop{\mathrm{Spec}}(R/I) \to \mathop{\mathrm{Spec}}(R)$ we have $\text{WeakAss}_{R/I}(M) = \text{WeakAss}_ R(M)$.

**Proof.**
Special case of Lemma 10.66.13.
$\square$

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## Comments (2)

Comment #3772 by Laurent Moret-Bailly on

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