Lemma 13.6.2. Let F : \mathcal{D} \to \mathcal{D}' be an exact functor of pre-triangulated categories. Let \mathcal{D}'' be the full subcategory of \mathcal{D} with objects
\mathop{\mathrm{Ob}}\nolimits (\mathcal{D}'') = \{ X \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{D}) \mid F(X) = 0\}
Then \mathcal{D}'' is a strictly full saturated pre-triangulated subcategory of \mathcal{D}. If \mathcal{D} is a triangulated category, then \mathcal{D}'' is a triangulated subcategory.
Proof.
It is clear that \mathcal{D}'' is preserved under [1] and [-1]. If (X, Y, Z, f, g, h) is a distinguished triangle of \mathcal{D} and F(X) = F(Y) = 0, then also F(Z) = 0 as (F(X), F(Y), F(Z), F(f), F(g), F(h)) is distinguished. Hence we may apply Lemma 13.4.16 to see that \mathcal{D}'' is a pre-triangulated subcategory (respectively a triangulated subcategory if \mathcal{D} is a triangulated category). The final assertion of being saturated follows from F(X) \oplus F(Y) = 0 \Rightarrow F(X) = F(Y) = 0.
\square
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Comment #8350 by Elías Guisado on
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