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Lemma 13.25.1. Let \mathcal{A} be an abelian category with enough injectives Let F : \mathcal{A} \to \mathcal{B} be an additive functor into an abelian category. Let (i, j) be a resolution functor, see Definition 13.23.2. The right derived functor RF of F fits into the following 2-commutative diagram

\xymatrix{ D^{+}(\mathcal{A}) \ar[rd]_{RF} \ar[rr]^{j'} & & K^{+}(\mathcal{I}) \ar[ld]^ F \\ & D^{+}(\mathcal{B}) }

where j' is the functor from Lemma 13.23.6.

Proof. By Lemma 13.20.1 we have RF(K^\bullet ) = F(j(K^\bullet )). \square


Comments (1)

Comment #723 by Kestutis Cesnavicius on

Right before this lemma a closing parenthesis is missing.

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