Lemma 37.61.6. Let $f : X \to S$ be a morphism of schemes. Assume $S$ is regular and $f$ is locally of finite type. Then $f$ is perfect.
Proof. See More on Algebra, Lemma 15.82.5. $\square$
Lemma 37.61.6. Let $f : X \to S$ be a morphism of schemes. Assume $S$ is regular and $f$ is locally of finite type. Then $f$ is perfect.
Proof. See More on Algebra, Lemma 15.82.5. $\square$
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