Lemma 37.61.6 (068B)—The Stacks project

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Table of contents
Part 2: Schemes
Chapter 37: More on Morphisms
Section 37.61: Perfect morphisms
Lemma 37.61.6 (cite)

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Lemma 37.61.6. Let $f : X \to S$ be a morphism of schemes. Assume $S$ is regular and $f$ is locally of finite type. Then $f$ is perfect.

Proof. See More on Algebra, Lemma 15.82.5. $\square$

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