Lemma 29.16.6. Let f : T \to S be a morphism of schemes. If f is locally of finite type and surjective, then f(T_{\text{ft-pts}}) = S_{\text{ft-pts}}.
Proof. We have f(T_{\text{ft-pts}}) \subset S_{\text{ft-pts}} by Lemma 29.16.5. Let s \in S be a finite type point. As f is surjective the scheme T_ s = \mathop{\mathrm{Spec}}(\kappa (s)) \times _ S T is nonempty, therefore has a finite type point t \in T_ s by Lemma 29.16.4. Now T_ s \to T is a morphism of finite type as a base change of s \to S (Lemma 29.15.4). Hence the image of t in T is a finite type point by Lemma 29.16.5 which maps to s by construction. \square
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