Lemma 96.15.1. Let \mathcal{X} be an algebraic stack over S.
If [U/R] \to \mathcal{X} is a presentation of \mathcal{X} then there is a canonical equivalence \mathit{QCoh}(\mathcal{O}_\mathcal {X}) \cong \mathit{QCoh}(U, R, s, t, c).
The category \mathit{QCoh}(\mathcal{O}_\mathcal {X}) is abelian.
The inclusion functor \mathit{QCoh}(\mathcal{O}_\mathcal {X}) \to \textit{Mod}(\mathcal{O}_\mathcal {X}) is right exact but not exact in general.
The category \mathit{QCoh}(\mathcal{O}_\mathcal {X}) has colimits and they agree with colimits in the category \textit{Mod}(\mathcal{O}_\mathcal {X}).
Given \mathcal{F}, \mathcal{G} in \mathit{QCoh}(\mathcal{O}_\mathcal {X}) the tensor product \mathcal{F} \otimes _{\mathcal{O}_\mathcal {X}} \mathcal{G} in \textit{Mod}(\mathcal{O}_\mathcal {X}) is an object of \mathit{QCoh}(\mathcal{O}_\mathcal {X}).
Given \mathcal{F}, \mathcal{G} in \mathit{QCoh}(\mathcal{O}_\mathcal {X}) with \mathcal{F} finite locally free the sheaf \mathop{\mathcal{H}\! \mathit{om}}\nolimits _{\mathcal{O}_\mathcal {X}}(\mathcal{F}, \mathcal{G}) in \textit{Mod}(\mathcal{O}_\mathcal {X}) is an object of \mathit{QCoh}(\mathcal{O}_\mathcal {X}).
Given a short exact sequence 0 \to \mathcal{F}_1 \to \mathcal{F}_2 \to \mathcal{F}_3 \to 0 in \textit{Mod}(\mathcal{O}_\mathcal {X}) with \mathcal{F}_1 and \mathcal{F}_3 quasi-coherent, then \mathcal{F}_2 is quasi-coherent.
Comments (0)