Lemma 46.9.2. Let U = \mathop{\mathrm{Spec}}(A) be an affine scheme. Let M, N be A-modules. For all i we have a canonical isomorphism
functorial in M and N.
Lemma 46.9.2. Let U = \mathop{\mathrm{Spec}}(A) be an affine scheme. Let M, N be A-modules. For all i we have a canonical isomorphism
functorial in M and N.
Proof. Let us construct a canonical arrow from right to left. Namely, if N \to I^\bullet is a pure injective resolution, then M^ a \to (I^\bullet )^ a is an exact complex of (adequate) \mathcal{O}-modules. Hence any element of \text{Pext}^ i_ A(M, N) gives rise to a map N^ a \to M^ a[i] in D(\mathcal{O}), i.e., an element of the group on the left.
To prove this map is an isomorphism, note that we may replace \mathop{\mathrm{Ext}}\nolimits ^ i_{\textit{Mod}(\mathcal{O})}(M^ a, N^ a) by \mathop{\mathrm{Ext}}\nolimits ^ i_{\textit{Adeq}(\mathcal{O})}(M^ a, N^ a), see Lemma 46.7.6. Let \mathcal{A} be the category of adequate functors on \textit{Alg}_ A. We have seen that \mathcal{A} is equivalent to \textit{Adeq}(\mathcal{O}), see Lemma 46.5.3; see also the proof of Lemma 46.7.3. Hence now it suffices to prove that
However, this is clear from Lemma 46.9.1 as a pure injective resolution N \to I^\bullet exactly corresponds to an injective resolution of \underline{N} in \mathcal{A}. \square
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