Lemma 15.41.1. Let $\varphi : R \to S$ be a ring map. Assume

$\varphi $ is regular,

$S$ is Noetherian, and

$R$ is Noetherian and reduced.

Then $S$ is reduced.

Lemma 15.41.1. Let $\varphi : R \to S$ be a ring map. Assume

$\varphi $ is regular,

$S$ is Noetherian, and

$R$ is Noetherian and reduced.

Then $S$ is reduced.

**Proof.**
For Noetherian rings being reduced is the same as having properties $(S_1)$ and $(R_0)$, see Algebra, Lemma 10.151.3. Hence we may apply Algebra, Lemmas 10.157.4 and 10.157.5.
$\square$

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