In this subsection we bound the regularity of quotients of a given coherent sheaf on \mathbf{P}^ n in terms of the Hilbert polynomial.
Proof.
We prove this by induction on n. If n = 0, then \mathbf{P}^ n_ k = \mathop{\mathrm{Spec}}(k) and any coherent module is 0-regular and any surjective map is surjective on global sections. Assume n > 0. Consider an exact sequence as in the lemma. Let P' \in \mathbf{Q}[t] be the polynomial P'(t) = P(t) - P(t - 1). Let m' be the integer which works for n - 1, r, and P'. By Lemmas 33.35.8 and 33.33.4 we may replace k by a field extension, hence we may assume k is infinite. Apply Lemma 33.35.3 to the coherent sheaf \mathcal{F}. The Hilbert polynomial of \mathcal{F}' = i^*\mathcal{F} is P' (see proof of Lemma 33.35.14). Since i^* is right exact we see that \mathcal{F}' is a quotient of \mathcal{O}_ H^{\oplus r} = i^*\mathcal{O}^{\oplus r}. Thus the induction hypothesis applies to \mathcal{F}' on H \cong \mathbf{P}^{n - 1}_ k (Lemma 33.35.2). Note that the map \mathcal{K}(-1) \to \mathcal{K} is injective as \mathcal{K} \subset \mathcal{O}^{\oplus r} and has cokernel i_*\mathcal{H} where \mathcal{H} = i^*\mathcal{K}. By the snake lemma (Homology, Lemma 12.5.17) we obtain a commutative diagram with exact columns and rows
\xymatrix{ & 0 \ar[d] & 0 \ar[d] & 0 \ar[d] \\ 0 \ar[r] & \mathcal{K}(-1) \ar[r] \ar[d] & \mathcal{O}^{\oplus r}(-1) \ar[r] \ar[d] & \mathcal{F}(-1) \ar[d] \ar[r] & 0 \\ 0 \ar[r] & \mathcal{K} \ar[r] \ar[d] & \mathcal{O}^{\oplus r} \ar[r] \ar[d] & \mathcal{F} \ar[d] \ar[r] & 0\\ 0 \ar[r] & i_*\mathcal{H} \ar[r] \ar[d] & i_*\mathcal{O}_ H^{\oplus r} \ar[r] \ar[d] & i_*\mathcal{F}' \ar[r] \ar[d] & 0 \\ & 0 & 0 & 0 }
Thus the induction hypothesis applies to the exact sequence 0 \to \mathcal{H} \to \mathcal{O}_ H^{\oplus r} \to \mathcal{F}' \to 0 on H \cong \mathbf{P}^{n - 1}_ k (Lemma 33.35.2) and \mathcal{H} is m'-regular. Recall that this implies that \mathcal{H} is d-regular for all d \geq m' (Lemma 33.35.10).
Let i \geq 2 and d \geq m'. It follows from the long exact cohomology sequence associated to the left column of the diagram above and the vanishing of H^{i - 1}(H, \mathcal{H}(d)) that the map
H^ i(\mathbf{P}^ n_ k, \mathcal{K}(d - 1)) \longrightarrow H^ i(\mathbf{P}^ n_ k, \mathcal{K}(d))
is injective. As these groups are zero for d \gg 0 (Cohomology of Schemes, Lemma 30.14.1) we conclude H^ i(\mathbf{P}^ n_ k, \mathcal{K}(d)) are zero for all d \geq m' and i \geq 2.
We still have to control H^1. First we observe that all the maps
H^1(\mathbf{P}^ n_ k, \mathcal{K}(m' - 1)) \to H^1(\mathbf{P}^ n_ k, \mathcal{K}(m')) \to H^1(\mathbf{P}^ n_ k, \mathcal{K}(m' + 1)) \to \ldots
are surjective by the vanishing of H^1(H, \mathcal{H}(d)) for d \geq m'. Suppose d > m' is such that
H^1(\mathbf{P}^ n_ k, \mathcal{K}(d - 1)) \longrightarrow H^1(\mathbf{P}^ n_ k, \mathcal{K}(d))
is injective. Then H^0(\mathbf{P}^ n_ k, \mathcal{K}(d)) \to H^0(H, \mathcal{H}(d)) is surjective. Consider the commutative diagram
\xymatrix{ H^0(\mathbf{P}^ n_ k, \mathcal{K}(d)) \otimes _ k H^0(\mathbf{P}^ n_ k, \mathcal{O}(1)) \ar[r] \ar[d] & H^0(\mathbf{P}^ n_ k, \mathcal{K}(d + 1)) \ar[d] \\ H^0(H, \mathcal{H}(d)) \otimes _ k H^0(H, \mathcal{O}_ H(1)) \ar[r] & H^0(H, \mathcal{H}(d + 1)) }
By Lemma 33.35.11 we see that the bottom horizontal arrow is surjective. Hence the right vertical arrow is surjective. We conclude that
H^1(\mathbf{P}^ n_ k, \mathcal{K}(d)) \longrightarrow H^1(\mathbf{P}^ n_ k, \mathcal{K}(d + 1))
is injective. By induction we see that
H^1(\mathbf{P}^ n_ k, \mathcal{K}(d - 1)) \to H^1(\mathbf{P}^ n_ k, \mathcal{K}(d)) \to H^1(\mathbf{P}^ n_ k, \mathcal{K}(d + 1)) \to \ldots
are all injective and we conclude that H^1(\mathbf{P}^ n_ k, \mathcal{K}(d - 1)) = 0 because of the eventual vanishing of these groups. Thus the dimensions of the groups H^1(\mathbf{P}^ n_ k, \mathcal{K}(d)) for d \geq m' are strictly decreasing until they become zero. It follows that the regularity of \mathcal{K} is bounded by m' + \dim _ k H^1(\mathbf{P}^ n_ k, \mathcal{K}(m')). On the other hand, by the vanishing of the higher cohomology groups we have
\dim _ k H^1(\mathbf{P}^ n_ k, \mathcal{K}(m')) = - \chi (\mathbf{P}^ n_ k, \mathcal{K}(m')) + \dim _ k H^0(\mathbf{P}^ n_ k, \mathcal{K}(m'))
Note that the H^0 has dimension bounded by the dimension of H^0(\mathbf{P}^ n_ k, \mathcal{O}^{\oplus r}(m')) which is at most r{n + m' \choose n} if m' > 0 and zero if not. Finally, the term \chi (\mathbf{P}^ n_ k, \mathcal{K}(m')) is equal to r{n + m' \choose n} - P(m'). This gives a bound of the desired type finishing the proof of the lemma.
\square
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