Lemma 18.42.2. Let $\mathcal{C}$ be a site. Let $\Lambda $ be a ring and let $M$ and $Q$ be $\Lambda $-modules. If $Q$ is a finitely presented $\Lambda $-module, then we have $\underline{M \otimes _\Lambda Q}(U) = \underline{M}(U) \otimes _\Lambda Q$ for all $U \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{C})$.
Proof. Choose a presentation $\Lambda ^{\oplus m} \to \Lambda ^{\oplus n} \to Q \to 0$. This gives an exact sequence $M^{\oplus m} \to M^{\oplus n} \to M \otimes Q \to 0$. By Lemma 18.42.1 we obtain an exact sequence
\[ \underline{M}(U)^{\oplus m} \to \underline{M}(U)^{\oplus n} \to \underline{M \otimes Q}(U) \to 0 \]
which proves the lemma. (Note that taking sections over $U$ always commutes with finite direct sums, but not arbitrary direct sums.) $\square$
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