Definition 9.5.1. The *characteristic* of a field $F$ is $0$ if $\mathbf{Z} \subset F$, or is a prime $p$ if $p = 0$ in $F$. The *prime subfield of $F$* is the smallest subfield of $F$ which is either $\mathbf{Q} \subset F$ if the characteristic is zero, or $\mathbf{F}_ p \subset F$ if the characteristic is $p > 0$.

## 9.5 The characteristic of a field

In the category of rings, there is an *initial object* $\mathbf{Z}$: any ring $R$ has a map from $\mathbf{Z}$ into it in precisely one way. For fields, there is no such initial object. Nonetheless, there is a family of objects such that every field can be mapped into in exactly one way by exactly one of them, and in no way by the others.

Let $F$ be a field. Think of $F$ as a ring to get a ring map $f : \mathbf{Z} \to F$. The image of this ring map is a domain (as a subring of a field) hence the kernel of $f$ is a prime ideal in $\mathbf{Z}$. Hence the kernel of $f$ is either $(0)$ or $(p)$ for some prime number $p$.

In the first case we see that $f$ is injective, and in this case we think of $\mathbf{Z}$ as a subring of $F$. Moreover, since every nonzero element of $F$ is invertible we see that it makes sense to talk about $p/q \in F$ for $p, q \in \mathbf{Z}$ with $q \not= 0$. Hence in this case we may and we do think of $\mathbf{Q}$ as a subring of $F$. One can easily see that this is the smallest subfield of $F$ in this case.

In the second case, i.e., when $\mathop{\mathrm{Ker}}(f) = (p)$ we see that $\mathbf{Z}/(p) = \mathbf{F}_ p$ is a subring of $F$. Clearly it is the smallest subfield of $F$.

Arguing in this way we see that every field contains a smallest subfield which is either $\mathbf{Q}$ or finite equal to $\mathbf{F}_ p$ for some prime number $p$.

It is easy to see that if $E \subset F$ is a subfield, then the characteristic of $E$ is the same as the characteristic of $F$.

Example 9.5.2. The characteristic of $\mathbf{F}_ p$ is $p$, and that of $\mathbf{Q}$ is $0$.

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