Lemma 9.4.1. If $k$ is a field, then every $k$-module is free.
9.4 Vector spaces
One reason fields are so nice is that the theory of modules over fields (i.e. vector spaces), is very simple.
Proof. Indeed, by linear algebra we know that a $k$-module (i.e. vector space) $V$ has a basis $\mathcal{B} \subset V$, which defines an isomorphism from the free vector space on $\mathcal{B}$ to $V$. $\square$
Lemma 9.4.2. Every exact sequence of modules over a field splits.
Proof. This follows from Lemma 9.4.1 as every vector space is a projective module. $\square$
This is another reason why much of the theory in future chapters will not say very much about fields, since modules behave in such a simple manner. Note that Lemma 9.4.2 is a statement about the category of $k$-modules (for $k$ a field), because the notion of exactness is inherently arrow-theoretic, i.e., makes use of purely categorical notions, and can in fact be phrased within a so-called abelian category.
Henceforth, since the study of modules over a field is linear algebra, and since the ideal theory of fields is not very interesting, we shall study what this chapter is really about: extensions of fields.
Post a comment
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$
). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
All contributions are licensed under the GNU Free Documentation License.
Comments (0)