Lemma 9.12.13. Let $E/k$ be a field extension. Then the elements of $E$ separable over $k$ form a subextension of $E/k$.
Proof. Let $\alpha , \beta \in E$ be separable over $k$. Then $\beta $ is separable over $k(\alpha )$ by Lemma 9.12.3. By Lemma 9.12.10 (applied with $n = 2$, $\alpha _1 = \alpha $, and $\alpha _2 = \beta $) we see that $k(\alpha , \beta )$ is separable over $k$. $\square$
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