Processing math: 100%

The Stacks project

Lemma 33.38.8. Let X be a scheme. Let Z_1, \ldots , Z_ n \subset X be closed subschemes. Let \mathcal{L}_ i be an invertible sheaf on Z_ i. Assume that

  1. X is reduced,

  2. X = \bigcup Z_ i set theoretically, and

  3. Z_ i \cap Z_ j is a discrete topological space for i \not= j.

Then there exists an invertible sheaf \mathcal{L} on X whose restriction to Z_ i is \mathcal{L}_ i. Moreover, if we are given sections s_ i \in \Gamma (Z_ i, \mathcal{L}_ i) which are nonvanishing at the points of Z_ i \cap Z_ j, then we can choose \mathcal{L} such that there exists a s \in \Gamma (X, \mathcal{L}) with s|_{Z_ i} = s_ i for all i.

Proof. The existence of \mathcal{L} can be deduced from Lemma 33.38.7 but we will also give a direct proof and we will use the direct proof to see the statement about sections is true. Set T = \bigcup _{i \not= j} Z_ i \cap Z_ j. As X is reduced we have

X \setminus T = \bigcup (Z_ i \setminus T)

as schemes. Assumption (3) implies T is a discrete subset of X. Thus for each t \in T we can find an open U_ t \subset X with t \in U_ t but t' \not\in U_ t for t' \in T, t' \not= t. By shrinking U_ t if necessary, we may assume that there exist isomorphisms \varphi _{t, i} : \mathcal{L}_ i|_{U_ t \cap Z_ i} \to \mathcal{O}_{U_ t \cap Z_ i}. Furthermore, for each i choose an open covering

Z_ i \setminus T = \bigcup \nolimits _ j U_{ij}

such that there exist isomorphisms \varphi _{i, j} : \mathcal{L}_ i|_{U_{ij}} \cong \mathcal{O}_{U_{ij}}. Observe that

\mathcal{U} : X = \bigcup U_ t \cup \bigcup U_{ij}

is an open covering of X. We claim that we can use the isomorphisms \varphi _{t, i} and \varphi _{i, j} to define a 2-cocycle with values in \mathcal{O}_ X^* for this covering that defines \mathcal{L} as in the statement of the lemma.

Namely, if i \not= i', then U_{i, j} \cap U_{i', j'} = \emptyset and there is nothing to do. For U_{i, j} \cap U_{i, j'} we have \mathcal{O}_ X(U_{i, j} \cap U_{i, j'}) = \mathcal{O}_{Z_ i}(U_{i, j} \cap U_{i, j'}) by the first remark of the proof. Thus the transition function for \mathcal{L}_ i (more precisely \varphi _{i, j} \circ \varphi _{i, j'}^{-1}) defines the value of our cocycle on this intersection. For U_ t \cap U_{i, j} we can do the same thing. Finally, for t \not= t' we have

U_ t \cap U_{t'} = \coprod (U_ t \cap U_{t'}) \cap Z_ i

and moreover the intersection U_ t \cap U_{t'} \cap Z_ i is contained in Z_ i \setminus T. Hence by the same reasoning as before we see that

\mathcal{O}_ X(U_ t \cap U_{t'}) = \prod \mathcal{O}_{Z_ i}(U_ t \cap U_{t'} \cap Z_ i)

and we can use the transition functions for \mathcal{L}_ i (more precisely \varphi _{t, i} \circ \varphi _{t', i}^{-1}) to define the value of our cocycle on U_ t \cap U_{t'}. This finishes the proof of existence of \mathcal{L}.

Given sections s_ i as in the last assertion of the lemma, in the argument above, we choose U_ t such that s_ i|_{U_ t \cap Z_ i} is nonvanishing and we choose \varphi _{t, i} such that \varphi _{t, i}(s_ i|_{U_ t \cap Z_ i}) = 1. Then using 1 over U_ t and \varphi _{i, j}(s_ i|_{U_{i, j}}) over U_{i, j} will define a section of \mathcal{L} which restricts to s_ i over Z_ i. \square


Comments (0)

There are also:

  • 2 comment(s) on Section 33.38: One dimensional Noetherian schemes

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.