Lemma 20.16.1. Let X be a topological space. Let \mathcal{F} be an abelian sheaf. Then the map \check{H}^1(X, \mathcal{F}) \to H^1(X, \mathcal{F}) defined in (20.15.0.1) is an isomorphism.
Proof. Let \mathcal{U} be an open covering of X. By Lemma 20.11.5 there is an exact sequence
0 \to \check{H}^1(\mathcal{U}, \mathcal{F}) \to H^1(X, \mathcal{F}) \to \check{H}^0(\mathcal{U}, \underline{H}^1(\mathcal{F}))
Thus the map is injective. To show surjectivity it suffices to show that any element of \check{H}^0(\mathcal{U}, \underline{H}^1(\mathcal{F})) maps to zero after replacing \mathcal{U} by a refinement. This is immediate from the definitions and the fact that \underline{H}^1(\mathcal{F}) is a presheaf of abelian groups whose sheafification is zero by locality of cohomology, see Lemma 20.7.2. \square
Comments (0)
There are also: