Lemma 66.22.5. Let S be a scheme. Let f : X \to Y be an étale morphism of algebraic spaces over S. Let x \in X. Then (1) \dim _ x(X) = \dim _{f(x)}(Y) and (2) the dimension of the local ring of X at x equals the dimension of the local ring of Y at f(x). If f is surjective, then (3) \dim (X) = \dim (Y).
Proof. Choose a scheme U and a point u \in U and an étale morphism U \to X which maps u to x. Then the composition U \to Y is also étale and maps u to f(x). Thus the statements (1) and (2) follow as the relevant integers are defined in terms of the behaviour of the scheme U at u. See Definition 66.9.1 for (1). Part (3) is an immediate consequence of (1), see Definition 66.9.2. \square
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