\begin{equation} \label{duality-equation-sheafy} (j')^* \circ a \to (j')^* \circ a \circ Rj_* \circ j^* \xrightarrow {\xi ^{-1}} (j')^* \circ Rj'_* \circ a' \circ j^* \to a' \circ j^* \end{equation}
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