Lemma 72.9.3. Let S be a scheme. Let X be an algebraic space over S. Let x \in |X|. If X is separated, locally Noetherian, and the dimension of the local ring of X at x is \leq 1 (Properties of Spaces, Definition 66.10.2), then there exists an open subspace of X containing x which is a scheme.
Separated algebraic spaces are schemes in codimension 1.
Proof. (Please see the remark below for a different approach avoiding the material on finite groupoids.) We can replace X by an quasi-compact neighbourhood of x, hence we may assume X is quasi-compact, separated, and Noetherian. There exists a scheme U and a finite surjective morphism U \to X, see Limits of Spaces, Proposition 70.16.1. Let R = U \times _ X U. Then j : R \to U \times _ S U is an equivalence relation and we obtain a groupoid scheme (U, R, s, t, c) over S with s, t finite and U Noetherian and separated. Let \{ u_1, \ldots , u_ n\} \subset U be the set of points mapping to x. Then \dim (\mathcal{O}_{U, u_ i}) \leq 1 by Decent Spaces, Lemma 68.12.6.
By More on Groupoids, Lemma 40.14.10 there exists an R-invariant affine open W \subset U containing the orbit \{ u_1, \ldots , u_ n\} . Since U \to X is finite surjective the continuous map |U| \to |X| is closed surjective, hence submersive by Topology, Lemma 5.6.5. Thus f(W) is open and there is an open subspace X' \subset X with f : W \to X' a surjective finite morphism. Then X' is an affine scheme by Cohomology of Spaces, Lemma 69.17.3 and the proof is finished. \square
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