The Stacks project

Lemma 15.121.1. Let $R$ be a regular local ring. Let $f \in R$. Then $\mathop{\mathrm{Pic}}\nolimits (R_ f) = 0$.

Proof. Let $L$ be an invertible $R_ f$-module. In particular $L$ is a finite $R_ f$-module. There exists a finite $R$-module $M$ such that $M_ f \cong L$, see Algebra, Lemma 10.126.3. By Algebra, Proposition 10.110.1 we see that $M$ has a finite free resolution $F_\bullet $ over $R$. It follows that $L$ is quasi-isomorphic to a finite complex of free $R_ f$-modules. Hence by Lemma 15.119.1 we see that $[L_ f] = n[R_ f]$ in $K_0(R_ f)$ for some $n \in \mathbf{Z}$. Applying the map of Lemma 15.118.7 we see that $L$ is trivial. $\square$

Comments (3)

Comment #8716 by Kentaro Inoue on

I suspect that the argument in the last two sentences is not correct because does not necessary belong to . I think that it is easy to use the surjectivity of the map .

Comment #8717 by Laurent Moret-Bailly on

@#8716: I think it suffices to substitute " in " in the penultimate sentence.

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  • 2 comment(s) on Section 15.121: A regular local ring is a UFD

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