Lemma 10.61.2. A Noetherian ring with finitely many primes has dimension \leq 1.
Proof. Let R be a Noetherian ring with finitely many primes. If R is a local domain, then the lemma follows from Lemma 10.61.1. If R is a domain, then R_\mathfrak m has dimension \leq 1 for all maximal ideals \mathfrak m by the local case. Hence \dim (R) \leq 1 by Lemma 10.60.4. If R is general, then \dim (R/\mathfrak q) \leq 1 for every minimal prime \mathfrak q of R. Since every prime contains a minimal prime (Lemma 10.17.2), this implies \dim (R) \leq 1. \square
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