The Stacks project

Lemma 65.11.1. Let $S$ be a scheme contained in $\mathit{Sch}_{fppf}$. Let $F$ be a sheaf on $(\mathit{Sch}/S)_{fppf}$ such that there exists $U \in \mathop{\mathrm{Ob}}\nolimits ((\mathit{Sch}/S)_{fppf})$ and a map $U \to F$ which is representable, surjective, and étale. Then $F$ is an algebraic space.

Proof. Set $R = U \times _ F U$. This is a scheme as $U \to F$ is assumed representable. The projections $s, t : R \to U$ are étale as $U \to F$ is assumed étale. The map $j = (t, s) : R \to U \times _ S U$ is a monomorphism and an equivalence relation as $R = U \times _ F U$. By Theorem 65.10.5 the quotient sheaf $F' = U/R$ is an algebraic space and $U \to F'$ is surjective and étale. Again since $R = U \times _ F U$ we obtain a canonical factorization $U \to F' \to F$ and $F' \to F$ is an injective map of sheaves. On the other hand, $U \to F$ is surjective as a map of sheaves by Lemma 65.5.9. Thus $F' \to F$ is also surjective and we conclude $F' = F$ is an algebraic space. $\square$


Comments (1)

Comment #11671 by on

Here's an argument for injectivity of . Write for the presheaf 39.20.0.1. Since is separated (see #11670), the following Lemma says that injectivity of amounts to injectivity of . But the latter injectivity is clear.

Lemma. Let be a site. Let be a separated presheaf of sets on and write for the sheafification of . Let be a presheaf of sets on . A morphism of presheaves is injective if and only if is injective.

(I guess this Lemma could fit to either Section 7.10 or 7.11.)

Proof. (). The morphism is injective by Sites, Theorem 7.10.10, (2). Hence so is the composite .

(). Let be sections of over that become equal when mapped into . Let be a cover of such that for each , and come from sections of over (Sites, Lemma 7.10.16). Since is injective, we deduce . Thus , for is a sheaf.


Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 0BGQ. Beware of the difference between the letter 'O' and the digit '0'.