Lemma 72.4.6. Let S be a scheme. Let X be a normal integral algebraic space over S. Then \Gamma (X, \mathcal{O}_ X) is a normal domain.
Proof. Set R = \Gamma (X, \mathcal{O}_ X). Then R is a domain by Lemma 72.4.4. Let f = a/b be an element of the fraction field of R which is integral over R. For any U \to X étale with U a scheme there is at most one f_ U \in \Gamma (U, \mathcal{O}_ U) with b|_ U f_ U = a|_ U. Namely, U is reduced and the generic points of U map to the generic point of X which implies that b|_ U is a nonzerodivisor. For every x \in |X| we choose U \to X as in Lemma 72.4.5. Then there is a unique f_ U \in \Gamma (U, \mathcal{O}_ U) with b|_ U f_ U = a|_ U because \Gamma (U, \mathcal{O}_ U) is a normal domain by Properties, Lemma 28.7.9. By the uniqueness mentioned above these f_ U glue and define a global section f of the structure sheaf, i.e., of R. \square
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