Proof.
By Lemmas 58.4.1 and 58.4.2 we may assume that H is fully faithful, h is surjective, H' \circ H maps objects to disjoint unions of the final object, and h \circ h' is trivial. Let N \subset G' be the smallest closed normal subgroup containing the image of h'. It is clear that N \subset \mathop{\mathrm{Ker}}(h). We may assume the functors H and H' are the canonical functors \textit{Finite-}G\textit{-Sets} \to \textit{Finite-}G'\textit{-Sets} \to \textit{Finite-}G''\textit{-Sets} determined by h and h'.
Suppose that (2) holds. This means that for a finite G'-set X' such that G'' acts trivially, the action of G' factors through G. Apply this to X' = G'/U'N where U' is a small open subgroup of G'. Then we see that \mathop{\mathrm{Ker}}(h) \subset U'N for all U'. Since N is closed this implies \mathop{\mathrm{Ker}}(h) \subset N, i.e., (1) holds.
Suppose that (1) holds. This means that N = \mathop{\mathrm{Ker}}(h). Let X' be a finite G'-set such that G'' acts trivially. This means that \mathop{\mathrm{Ker}}(G' \to \text{Aut}(X')) is a closed normal subgroup containing \mathop{\mathrm{Im}}(h'). Hence N = \mathop{\mathrm{Ker}}(h) is contained in it and the G'-action on X' factors through G, i.e., (2) holds.
Suppose that (3) holds. This means that for a finite G'-set X' such that G'' acts trivially, there is a surjection of G'-sets X \to X' where X is a G-set. Clearly this means the action of G' on X' factors through G, i.e., (2) holds.
The implication (2) \Rightarrow (3) is immediate. This finishes the proof.
\square
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