Lemma 58.12.2. A normal local ring with separably closed fraction field is strictly henselian.
Proof. Let (A, \mathfrak m, \kappa ) be normal local with separably closed fraction field K. If A = K, then we are done. If not, then the residue field \kappa is algebraically closed by Lemma 58.12.1 and it suffices to check that A is henselian. Let f \in A[T] be monic and let a_0 \in \kappa be a root of multiplicity 1 of the reduction \overline{f} \in \kappa [T]. Let f = \prod f_ i be the factorization in K[T]. By Algebra, Lemma 10.38.5 we have f_ i \in A[T]. Thus a_0 is a root of f_ i for some i. After replacing f by f_ i we may assume f is irreducible. Then, since the derivative f' cannot be zero in A[T] as a_0 is a single root, we conclude that f is linear due to the fact that K is separably algebraically closed. Thus A is henselian, see Algebra, Definition 10.153.1. \square
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