Lemma 33.5.3. Notation as in Lemma 33.5.1. Assume X is locally of finite type over k, that \dim (\mathcal{O}_{X, x}) = \dim (\mathcal{O}_{Y, y}) and that \kappa (x) \otimes _ k K is reduced (for example if \kappa (x)/k is separable or K/k is separable). Then \mathfrak m_ x \mathcal{O}_{Y, y} = \mathfrak m_ y.
Proof. (The parenthetical statement follows from Algebra, Lemma 10.43.6.) Combining Lemmas 33.5.1 and 33.5.2 we see that \mathcal{O}_{Y, y}/\mathfrak m_ x \mathcal{O}_{Y, y} has dimension 0 and is reduced. Hence it is a field. \square
Comments (0)
There are also: