Processing math: 100%

The Stacks project

Lemma 55.11.3. In Situation 55.9.3 with \kappa _ i = H^0(C_ i, \mathcal{O}_{C_ i}) and g_ i the genus of C_ i the data

n, m_ i, (C_ i \cdot C_ j), [\kappa _ i : k], g_ i

is a numerical type of genus equal to the genus of C.

Proof. (In the proof of Lemma 55.11.2 we have seen that the quantities used in the statement of the lemma are well defined.) We have to verify the conditions (1) – (5) of Definition 55.3.1.

Condition (1) is immediate.

Condition (2). Symmetry of the matrix (C_ i \cdot C_ j) follows from Equation (55.9.6.1) and Lemma 55.9.6. Nonnegativity of (C_ i \cdot C_ j) for i \not= j is part (1) of Lemma 55.9.7.

Condition (3) is part (3) of Lemma 55.9.7.

Condition (4) is part (2) of Lemma 55.9.7.

Condition (5) follows from the fact that (C_ i \cdot C_ j) is the degree of an invertible module on C_ i which is divisible by [\kappa _ i : k], see Varieties, Lemma 33.44.10.

The genus formula proved in Lemma 55.11.2 tells us that the numerical type has the genus as stated, see Definition 55.3.4. \square


Comments (0)


Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.