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The Stacks project

Lemma 101.38.2. Let f : \mathcal{X} \to \mathcal{Y} be a morphism of algebraic stacks. Let g : \mathcal{W} \to \mathcal{X} be a morphism of algebraic stacks which is surjective, flat, and locally of finite presentation. Then the scheme theoretic image of f exists if and only if the scheme theoretic image of f \circ g exists and if so then these scheme theoretic images are the same.

Proof. Assume \mathcal{Z} \subset \mathcal{Y} is a closed substack and f \circ g factors through \mathcal{Z}. To prove the lemma it suffices to show that f factors through \mathcal{Z}. Consider a scheme T and a morphism T \to \mathcal{X} given by an object x of the fibre category of \mathcal{X} over T. We will show that f(x) is in fact in the fibre category of \mathcal{Z} over T. Namely, the projection T \times _\mathcal {X} \mathcal{W} \to T is a surjective, flat, locally finitely presented morphism. Hence there is an fppf covering \{ T_ i \to T\} such that T_ i \to T factors through T \times _\mathcal {X} \mathcal{W} \to T for all i. Then T_ i \to \mathcal{X} factors through \mathcal{W} and hence T_ i \to \mathcal{Y} factors through \mathcal{Z}. Thus x|_{T_ i} is an object of \mathcal{Z}. Since \mathcal{Z} is a strictly full substack, we conclude that x is an object of \mathcal{Z} as desired. \square


Comments (2)

Comment #8099 by Shizhang on

Line 3 of the proof: should it be `` is in fact in the fibre category...''?


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